I'd like a function that maps a function f over a sequence xs, and if f(x) (where x is an element of xs) produces a Failure then don't process any further elements of xs but immediately return Failure. If f(x) succeeds for all x then return a Success containing a sequence of the results.
So the type signature might be something like
def traverse[A, B](xs: Seq[A])(f: A => Try[B]): Try[Seq[B]]
And some test cases:
def doWork(i: Int): Try[Int] = {
i match {
case 1 => Success(10)
case 2 => Failure(new IllegalArgumentException("computer says no"))
case 3 => Success(30)
}
}
traverse(Seq(1,2,3))(doWork)
res0: scala.util.Try[Seq[Int]] = Failure(java.lang.IllegalArgumentException: computer says no)
traverse(Seq(1,3))(doWork)
scala.util.Try[Seq[Int]] = Success(List(10, 30))
What would be the most elegant way to implement this?
Simple implementation:
def traverse[A, B](xs: Seq[A])(f: A => Try[B]): Try[Seq[B]] =
xs.foldLeft[Try[Seq[B]]](Success(Vector())) { (attempt, elem) => for {
seq <- attempt
next <- f(elem)
} yield seq :+ next
}
Trouble here that while function will not evaluate f after the Failure will occur, function will traverse the sequence to the end , which could be undesirable in case of some complex Stream, so we may use some specialized version:
def traverse1[A, B](xs: Seq[A])(f: A => Try[B]): Try[Seq[B]] = {
val ys = xs map f
ys find (_.isFailure) match {
case None => Success(ys map (_.get))
case Some(Failure(ex)) => Failure(ex)
}
}
which uses intermediate collection, which leads to unnecessary memory overhead in case of strict collection
or we could reimplement fold from scratch:
def traverse[A, B](xs: Seq[A])(f: A => Try[B]): Try[Seq[B]] = {
def loop(xs: Seq[A], acc: Seq[B]): Try[Seq[B]] = xs match {
case Seq() => Success(acc)
case elem +: tail =>
f(elem) match {
case Failure(ex) => Failure(ex)
case Success(next) => loop(tail, acc :+ next)
}
}
loop(xs, Vector())
}
As we could see inner loop will continue iterations while it deals only with Success
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