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Running a function for specified duration : C++ with <chrono> [duplicate]

I need to implement a function that should do specified task for specified duration which is passed to it as parameter (std::chrono::milliseconds).

I have come up with code :

void Run(std::chrono::milliseconds ms)
{
    std::chrono::time_point<std::chrono::system_clock> start, end;
    start = std::chrono::system_clock::now();
    std::chrono::duration<double> elapsed_seconds = end - start;
    while (elapsed_seconds <= (ms / 1000))
    {
        std::cout << "Running" << std::endl;
        end = std::chrono::system_clock::now();
        elapsed_seconds = end - start;
    }
}

int main()
{
    {
        std::chrono::milliseconds ms(30000);
        Run(ms);
        system("Pause");
    }

I suppose the code to print Running for 30 seconds and then exit. But it does not do so. How do I achieve such behavior with C++ <chrono>

like image 448
Gaurav K Avatar asked Apr 27 '26 20:04

Gaurav K


1 Answers

All you really need is to know the end point and then loop until that point is reached:

#include <chrono>

void Run(std::chrono::milliseconds ms)
{
    std::chrono::time_point<std::chrono::system_clock> end;

    end = std::chrono::system_clock::now() + ms; // this is the end point

    while(std::chrono::system_clock::now() < end) // still less than the end?
    {
        std::cout << "Running" << std::endl;
    }
}

int main()
{
    std::chrono::milliseconds ms(3000);
    Run(ms);
    system("Pause");
}
like image 153
Galik Avatar answered Apr 29 '26 11:04

Galik