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Run-Time Check Failure #2 - Stack around the variable 'manager' was corrupted! and output screen does not stops even after using getchar();

Tags:

c++

visual-c++

i am working using visual c++ on windows 7. and getting the error error: Run-Time Check Failure #2 - Stack around the variable 'manager' was corrupted. what could be the solution ?

#include <iostream>
using namespace std;

class employee
{
    char  name[30];
    float age;
public:
    void getData(void);
    void putData(void);
};
void employee ::getData(void)
{
    cout<<"entr name";
    cin>> name;
    cout<<"entr age";
    cin>>age;
}
void employee ::putData(void)
{
    cout<<"name:"<< name<<endl;
    cout<<"age"<<age<<endl;
}
const int size=3;
int main()
{
    employee manager[size];
    for(int i=0; i<size; i++)
    {
        cout <<endl<<"details of manager "<<i++<<endl;
        manager[i].getData();
    }
    cout<<endl;
    for(int i=0;i<size;i++)
    {
        cout<< endl << "manager "<< i++ << endl;
        manager[i].putData();
    }
    getchar();
    return 0;
}

1 Answers

employee manager[size];
for(int i=0; i<size; i++)
{
    cout <<endl<<"details of manager "<<i++<<endl;
    // PROBLEM IS HERE ----------->>   ^^^^^
    manager[i].getData();
}

When you increment i on the last iteration it becomes equal to the size and manager[i] is out of bounds. I think you meant not to increment i inside the loop, because you not only get out of bounds but also skip managers at odd positions. So here's what I suppose you intended:

for(int i=0; i<size; i++)
{
    cout <<endl<<"details of manager "<<i<<endl;
    manager[i].getData();
}

Same refers to the other loop

like image 55
Armen Tsirunyan Avatar answered Dec 03 '25 00:12

Armen Tsirunyan



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