Running the following code
Dir.foreach(FileUtils.pwd()) do |f|
if f.end_with?('log')
File.open(f) do |file|
if File.size(f) > MAX_FILE_SIZE
puts f
puts file.ctime
puts file.mtime
# zipping the file
orig = f
Zlib::GzipWriter.open('arch_log.gz') do |gz|
gz.mtime = File.mtime(orig)
gz.orig_name = orig
gz.write IO.binread(orig)
puts "File has been archived"
end
#deleting the file
begin
File.delete(f)
puts "File has been deleted"
rescue Exception => e
puts "File #{f} can not be deleted"
puts " Error #{e.message}"
puts "======= Please remove file manually =========="
end
end
end
end
end
Also files are pretty heavy more than 1GB. Any help would be appreciated.
If the files you are reading are > 1GB, you have to have that much memory free at a minimum, because IO.binread is going to slurp that amount in.
You'd be better off to load a known amount and loop over the input until it's completely read, reading and writing in chunks.
From the docs:
IO.binread(name, [length [, offset]] ) -> string
------------------------------------------------------------------------------
Opens the file, optionally seeks to the given offset, then returns
length bytes (defaulting to the rest of the file). binread ensures
the file is closed before returning. The open mode would be "rb:ASCII-8BIT".
IO.binread("testfile") #=> "This is line one\nThis is line two\nThis is line three\nAnd so on...\n"
IO.binread("testfile", 20) #=> "This is line one\nThi"
IO.binread("testfile", 20, 10) #=> "ne one\nThis is line "
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