Return which digit occurs the most times

Question

I have to return which digit in a number occurs the most frequently ( though not how many times it occurs )

So far I can only get this, I don't know how to isolate the digit, only to show how many times each digit occurs.

#include <stdio.h>

int frequentDigit(int);

int main() 
{
    frequentDigit(123032333);
    return 0;
}

int frequentDigit(int arg) 
{
    int tmp;  int i;  int myArr[9] = { 0 };
    tmp = (arg < 0) ? -arg : arg;
    do
    {
        myArr[tmp % 10]++;   
        tmp /= 10;
    } while (tmp != 0);
    for (i = 0; i < 9; i++) { printf("\nThere are %d occurances of digit %d", myArr[i], i); }
}

Answer 1

The array where you are storing the frequency of the digits, i.e myArr[]. Its suppose to hold the frequency of all the number from 0...9. And since there are 10 numbers, you would need an array of lenght 10.

int myArr[10];

Later, you need to traverse through the array once, checking for the max element, and saving the index accordingly, to find which number has occured most number of times.

To traverse, the for loop should go till 9

for (i = 0; i <= 9; i++)

Edited

As someone commented, you can find the max value while you are computing the frequencies itself.

int max = -1, max_num = -1;
do
{
    myArr[tmp % 10]++;
    if( myArr[tmp % 10] > max)
    {
        max = myArr[tmp % 10];
        max_num = tmp % 10;
    }
    tmp /= 10;
} while (tmp != 0);
printf("%d", max_num);