Return numbers which appear only once (JavaScript)

Question

Say I have the array [1,2,3,5,2,1,4]. How do I get make JS return [3,4,5]?

I've looked at other questions here but they're all about delete the copies of a number which appears more than once, not both the original and the copies.

Thanks!

Answer 1

Use Array#filter method twice.

var data = [1, 2, 3, 5, 2, 1, 4];

// iterate over elements and filter
var res = data.filter(function(v) {
  // get the count of the current element in array
  // and filter based on the count
  return data.filter(function(v1) {
    // compare with current element
    return v1 == v;
    // check length
  }).length == 1;
});

console.log(res);

---

Or another way using Array#indexOf and Array#lastIndexOf methods.

var data = [1, 2, 3, 5, 2, 1, 4];

// iterate over the array element and filter out
var res = data.filter(function(v) {
  // filter out only elements where both last 
  // index and first index are the same.
  return data.indexOf(v) == data.lastIndexOf(v);
});

console.log(res);

Answer 2

You can also use .slice().sort()

var x = [1,2,3,5,2,1,4];
var y = x.slice().sort(); // the value of Y is sorted value X

var newArr = []; // define new Array

for(var i = 0; i<y.length; i++){ // Loop through array y
  if(y[i] != y[i+1]){ //check if value is single
    newArr.push(y[i]); // then push it to new Array
  }else{
    i++; // else skip to next value which is same as y[i]
  }
}


console.log(newArr);

If you check newArr it has value of:

[3, 4, 5]