Return Custom Exception while using wiremock

Question

I need to return custom exception while mocking a url like

whenever I will hit /test/user/get/ I need to return UserNotFoundException.

I m trying to do like this. Can somebody help me how to return exception in wiremock

 public void setupWiresMockStubs(String body, int status) {
        wireMockServer.stubFor(post(urlEqualTo(
            "/test/user/get"))
            .willReturn(aResponse().withHeader("Content-Type", "application/json")
                .withBody(body)
                .withStatus(status)));
      }

Answer 1

You cannot return an exception. The API should return a status code and a body.

Let's say your API returns BadRequest (http code 400) in case of exception UserNotFoundException:

@PostMapping(value = "/test/user/get")
public String myApi(@RequestParam String param1) {
    try {...
        } catch(UserNotFoundException e) {
    throw new ResponseStatusException(HttpStatus.BAD_REQUEST, "user not found");

You can mock the above API this way:

WireMock.stubFor(WireMock.post(WireMock.urlPathEqualTo("/test/user/get"))
            .willReturn(aResponse().withStatus(400).withBody("user not found")));

or even better - with predefined errors (ResponseDefinitionBuilder) in Wiremock:

WireMock.stubFor(WireMock.post(WireMock.urlPathEqualTo("/test/user/get"))
            .willReturn(badRequest().withBody("user not found")));

You have all kinds of predefined errors in Wiremock:

badRequest(), unauthorized(), notFound() etc.

https://github.com/wiremock/wiremock/blob/master/src/main/java/com/github/tomakehurst/wiremock/client/WireMock.java#L602