d={'Bat':1,'Tennisball':3,'Racquet':2,'Shuttlecock':3,'Javelin':1,'Soccer':1,'Hockey':7,'Gloves':8}
I want the last value of dictionary not key
The most efficient way, in O(1), is to use dict.popitem:
k, last_value = _, d[k] = d.popitem()
LIFO order is guaranteed since Python 3.7 (the same version when dictionary insertion ordering was guaranteed).
If the double assignment seems too tricky, consider
last_value = d[next(reversed(d))]
Here are the timing comparisons (CPython 3.10 on linux):
>>> d={'Bat':1,'Tennisball':3,'Racquet':2,'Shuttlecock':3,'Javelin':1,'Soccer':1,'Hockey':7,'Gloves':8}
>>> timeit k, last_value = _, d[k] = d.popitem()
107 ns ± 3.34 ns per loop (mean ± std. dev. of 7 runs, 10000000 loops each)
>>> timeit next(reversed(d.values()))
150 ns ± 0.237 ns per loop (mean ± std. dev. of 7 runs, 10000000 loops each)
>>> timeit d[next(reversed(d))]
134 ns ± 0.503 ns per loop (mean ± std. dev. of 7 runs, 10000000 loops each)
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