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RestTemplate.exchange() does not encode '+'?

The RestTemplate.exchange() will encode all the invalid characters in URL but not + as + is a valid URL character. But how to pass a + in any URL's query parameter?

like image 675
Raj Rajeshwar Singh Rathore Avatar asked Aug 28 '26 18:08

Raj Rajeshwar Singh Rathore


1 Answers

If the URI you pass to the RestTemplate has encoded set as true then it will not perform the encoding on the URI you pass else it will do.

import java.io.UnsupportedEncodingException;
import java.net.URI;
import java.net.URLEncoder;
import java.util.Collections;
import org.springframework.http.HttpEntity;
import org.springframework.http.HttpHeaders;
import org.springframework.http.HttpMethod;
import org.springframework.http.ResponseEntity;
import org.springframework.http.client.BufferingClientHttpRequestFactory;
import org.springframework.http.client.SimpleClientHttpRequestFactory;
import org.springframework.web.client.RestTemplate;
import org.springframework.web.util.UriComponentsBuilder;

class Scratch {

  public static void main(String[] args) {

    RestTemplate rest = new RestTemplate(
        new BufferingClientHttpRequestFactory(new SimpleClientHttpRequestFactory()));

    HttpHeaders headers = new HttpHeaders();
    headers.add("Content-Type", "application/json");
    headers.add("Accept", "application/json");
    HttpEntity<String> requestEntity = new HttpEntity<>(headers);

    UriComponentsBuilder builder = null;
    try {
      builder = UriComponentsBuilder.fromUriString("http://example.com/endpoint")
          .queryParam("param1", URLEncoder.encode("abc+123=", "UTF-8"));
    } catch (UnsupportedEncodingException e) {
      e.printStackTrace();
    }

    URI uri = builder.build(true).toUri();
    ResponseEntity responseEntity = rest.exchange(uri, HttpMethod.GET, requestEntity, String.class);
  }

}

So if you need to pass a query param with + in it then the RestTemplate will not encode the + but every other invalid URL character as + is a valid URL character. Hence you have to first encode the param (URLEncoder.encode("abc+123=", "UTF-8")) and then pass the encoded param to RestTemplate stating that the URI is already encoded using builder.build(true).toUri();, where true tells the RestTemplate that the URI is alrady encoded so not to encode again and hence the + will be passed as %2B.

  1. With builder.build(true).toUri(); OUTPUT : http://example.com/endpoint?param1=abc%2B123%3D as the encoding will be perfromed once.
  2. With builder.build().toUri(); OUTPUT : http://example.com/endpoint?param1=abc%252B123%253D as the encoding will be perfromed twice.
like image 199
Raj Rajeshwar Singh Rathore Avatar answered Aug 31 '26 09:08

Raj Rajeshwar Singh Rathore



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