Say I have the following data frame:
ID<-c(1,1,1,1,1,2,2,2,2,2,3,3,3,3,3, 4,4,4,4,4,5,5,5,5,5)
Score<- sample(1:20, 25, replace=TRUE)
days<-rep(c("Mon", "Tue", "Wed", "Thu", "Fri"), times=5)
t<-cbind(ID, Score, days)
I would like to reshape it so that the new columns are ID and the actual weekday names, (meaning 6 columns) and the Score values are distributed according to their ID and day name. Something like this:
I found that reshape package might do. Tried (melt and cast) but it did not produce the result I wanted, but something like in this post: Melt data for one column
A base R solution that uses the built-in reshape command.
set.seed(12345)
t <- data.frame(id = c(1,1,1,1,1,2,2,2,2,2,3,3,3,3,3,4,4,4,4,4,5,5,5,5,5),
score = sample(x = 1:20,size = 25,replace = TRUE),
days = rep(x = c("Mon","Tue","Wed","Thu","Fri"),times = 5))
t.wide <- reshape(data = t,
v.names = "score",
timevar = "days",
idvar = "id",
direction = "wide")
names(t.wide) <- gsub(pattern = "score.",replacement = "",x = names(t.wide),fixed = TRUE)
t.wide
id Mon Tue Wed Thu Fri
1 1 15 18 16 18 10
6 2 4 7 11 15 20
11 3 1 4 15 1 8
16 4 10 8 9 4 20
21 5 10 7 20 15 13
You can use reshape2 to do this, but you need a data.frame to do that. Using cbind produces a matrix. (And converts all your numerical variables to characters in this case, as matrices can only hold one data type).
I've changed your code to produce a dataframe, which is already in long format (one row per observation).
set.seed(123)
ID<-c(1,1,1,1,1,2,2,2,2,2,3,3,3,3,3, 4,4,4,4,4,5,5,5,5,5)
Score<- sample(1:20, 25, replace=TRUE)
days<-rep(c("Mon", "Tue", "Wed", "Thu", "Fri"), times=5)
dat<-data.frame(ID, Score, days)
Changing it to wide using reshape2 is then quite straightforward:
library(reshape2)
res <- dcast(ID~days,value.var="Score",data=dat)
> res
ID Fri Mon Thu Tue Wed
1 1 16 3 2 12 6
2 2 19 13 12 7 19
3 3 19 19 17 8 15
4 4 15 3 8 1 20
5 5 3 11 18 8 15
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