I'm using svg to embed stack overflow's logo into my resume. The svg xml contains the fill color of the logo.
Here is the svg content
<svg xmlns:svg="http://www.w3.org/2000/svg" xmlns="http://www.w3.org/2000/svg" version="1.1" width="100%" height="100%" viewBox="0 0 64 64" id="svg3715">
<defs id="defs3717"/>
<g id="layer1">
<path d="m 9.3049611,36.847632 4.4013079,0.04316 -0.153442,19.598393 29.291259,0 0,-19.527506 4.637782,0 0,24.287331 -38.2006795,0 0.023777,-24.401371 z" id="path2830" fill="#919191" style="fill-opacity:1;stroke:none"/>
<rect width="22.944817" height="4.881876" x="16.481951" y="48.434078" id="rect3604" fill="#919191" style="fill-opacity:1;stroke:none"/>
<rect width="23.066864" height="5.0039229" x="20.749949" y="37.830307" transform="matrix(0.9953749,0.09606666,-0.09606666,0.9953749,0,0)" id="rect3606" fill="#A78B68" style="fill-opacity:1;stroke:none"/>
<rect width="23.066864" height="5.0039229" x="26.472515" y="23.401554" transform="matrix(0.96240291,0.27162592,-0.27162592,0.96240291,0,0)" id="rect3606-1" fill="#c19653" style="fill-opacity:1;stroke:none"/>
<rect width="23.066864" height="5.0039229" x="30.528769" y="3.1535864" transform="matrix(0.85597805,0.51701216,-0.51701216,0.85597805,0,0)" id="rect3606-1-3" fill="#D48C28" style="fill-opacity:1;stroke:none"/>
<rect width="23.066864" height="5.0039229" x="27.191883" y="-24.475019" transform="matrix(0.58242689,0.81288309,-0.81288309,0.58242689,0,0)" id="rect3606-1-3-7" fill="#FE8908" style="fill-opacity:1;stroke:none"/>
<rect width="23.066864" height="5.0039229" x="11.174569" y="-50.183693" transform="matrix(0.16480989,0.98632535,-0.98632535,0.16480989,0,0)" id="rect3606-1-3-7-6" fill="#FF7A15" style="fill-opacity:1;stroke:none"/>
</g>
</svg>
I can set the logo to be black (what I want it to look like on normal state) using
rect, path
{
fill: black;
}
But now, what can I do to remove the property on :hover, in order to have the logo find back it's brightness ?
I tried to look on the fill parameters documentation. But I found nothing helping.
It is possible - simply use the :not() selector in CSS. Some browsers might not support it though:
svg:not(:hover) rect,
svg:not(:hover) path {
fill: black;
}
See fiddle here - http://jsfiddle.net/teddyrised/qvV8Q/
[Edit]: For the sake of completeness - should you want to add compatibility for browsers that do not support the :not() selector, you simply toggle a .hover class and style accordingly:
$(document).ready(function() {
$("svg").hover(function() {
$(this).attr("class", "hover");
}, function() {
$(this).attr("class", "");
});
});
Note: The reason why .attr() is used is because the add/removeClass method does not work with <svg> elements natively. However, this can be remedied by using this plugin - http://keith-wood.name/svg.html#dom
And the CSS:
.hover rect, .hover path {
fill: black;
}
The JS-powered alternative can be viewed here - http://jsfiddle.net/teddyrised/LTRCB/
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