Replace Value in Numpy array, with Value in a second Numpy array, Given Criteria

Question

I have 2 large arrays with the exact same ammount of elements.

Array1=[[1,2,3][1,1,2]]
Array2=[[0,2,0][3,1,3]]

if Element in Array1="1", Replace "1" with whatever is in the same place as Array2

Output=[[0,2,3][3,1,2]]

Should be easy, but this late on a friday has my brains scrambled.

Answer 1

import numpy as np

Array1 = np.array([[1,2,3], [1,1,2]])
Array2 = np.array([[0,2,0], [3,1,3]])

b = np.where(Array1 == 1)

Array1[b] = Array2[b]

Result:

>>> Array1
array([[0, 2, 3],
       [3, 1, 2]])

As jorgeca pointed out the above solution can be reduced to:

b = Array1 == 1
Array1[b] = Array2[b]

Answer 2

This one's based on Akaval's solution, but in one line. It takes advantage of other features of np.where():

import numpy as np
Array1 = np.array([[1,2,3], [1,1,2]])  
Array2 = np.array([[0,2,0], [3,1,3]])

Output = np.where(Array1 == 1, Array2, Array1)