Replace blank spaces in an array in bash

Question

I have to replace blank spaces (" ") of all the values from an array in shell script. So, I need to make an array like this:

$ array[0]="one"
$ array[1]="two three"
$ array[2]="four five"

looks like this:

$ array[0]="one"
$ array[1]="two!three"
$ array[2]="four!five"

Replacing every blank space to another character with a loop or something, not changing value by value.

Answer 1

array=('one' 'two three' 'four five') # initial assignment
array=( "${array[@]// /_}" )          # perform expansion on all array members at once
printf '%s\n' "${array[@]}"           # print result