Remove entire querystring using regex

Question

I have the below regex, but how can I remove the querystring entirely if it is present:

^~/(.*)/restaurant/(.*)

eg. the url

/seattle/restaurant/sushi?page=2 

or

/seattle/restaurant/sushi?somethingelse=something 

or

/seatthe/restaurant/sushi 

should just return seattle and restaurant and sushi and remove any querystring if it is present.

(sorry for reposting a similar question, but I couldn't get the answer to work in my previous question).

thanks

Thomas

Answer 1

This regex:

(/[^?]+).*

Should match the initial section of your URL and put it in a group.

So it will match /seattle/restaurant/sushi and put the value in a group.

You can use something like this: (/.*?/restaurant[^?]+).* if you want to handle just URLs with the word restaurant as the second word between the slashes.

Edit: Something like so should yield 3 groups: /(.*?)/(restaurant)/([^?]+).*. Group 1 being seatthe, group 2 being restaurant and group 3 being sushi. If after the last / there is a ?, the regex discards the ? and everything which follows.