Regex replace punctuation with whitespace

Question

I have a word counter function but it doesn't account for people using poor punctuation, for example:

"hello.world"

That would only count is as 1 word.

Instead it should count that as 2 words.

So instead I need a regex to replace comma's, full stops and any whitespace that is 1+ with a single whitespace.

Here's what I have so far:

proWords = proWords.replace(/[,\s]/, '\s');

negWords = negWords.replace(/[,\s]/, '\s');

Answer 1

The replacement is just an ordinary string, it shouldn't contain regular expression escape sequences like \s.

proWords = proWords.replace(/[,.\s]+/g, ' ');

The + regular expression makes it replace any sequence of the characters, and you need the g modifier to replace multiple times.