Regex : One single character between 2 chars

Question

I searched a lot, but never found an answer to my question, and I'm desperate.

I would like to get all dots ( '.' ) between parenthesis wherever they are, and with and undefined number of parenthesis. The problem is that I can just get the first dot, but I don't know how to get all in the same group.

I tried this : \((?:[^\.]*)([\.])(?:[^\.]*)*\)

But it just works if there's just one dot.. Any idea please ?

Answer 1

Try this:

(\(|(\.)|\))

example: http://regex101.com/r/jV5yI0