Regex for a Function Call?

Question

I'm looking to simply pull some quoted text out of a function call and was wondering if I could get some help with regex?

The string would look something like this: 'MyFunction("MyStringArg");'

I would, essentially, like to scan a file for any lines that call 'MyFunction', and then capture the string literal within the quotes.

Follow-up Question
How would I go about avoiding commented lines with this?

Update
I was able to solve my problem with:
MyFunction\s*\(\s*"(.*?)\"\s*\)\s*;

Thanks @devyndraen and everyone for your help!

Answer 1

I'm not sure what kinds of requirements for formatting you have, so I included the assumption that there could be any amount of space in the normal programming places there could be some.

The resultant string will be in the \1 backreference.

MyFunction\s*\(\s*"(.*?)\"\s*\)\s*;

http://rubular.com/r/qVsaqJS6gJ

Answer 2

I would suggest this non-greedy regex with flag s (DOTALL in Java) (assuming there are no comments inside the parenthesis of this function call:

$regex = '/MyFunction.*?\(.*?"(.*?)".*?\).*?;/s';

If you use preg_match($regex, $str, $matches) then argument will be available in $matches[1].