Say I have a list x = [1, 2, 3, 4]
Is there a recursive method where i can go through the list to find the value?
I want to ultimately be able to compare a returned value in the list, (or nested list) to an arbitrary number to see it it matches.
I can think a way to do this using a for loop, but i have trouble imagining a recursive method to do the same thing. I know that I can't set a counter to keep track of my position in the list because calling the function recursively would just reset the counter every time.
I was thinking I could set my base case of the function as a comparison between the number and a list of len 1.
I just want some hints really.
This is not the way to do things in Python, but surely - you can traverse a list of lists recursively:
def findList(lst, ele):
if not lst: # base case: the list is empty
return False
elif lst[0] == ele: # check if current element is the one we're looking
return True
elif not isinstance(lst[0], list): # if current element is not a list
return findList(lst[1:], ele)
else: # if current element is a list
return findList(lst[0], ele) or findList(lst[1:], ele)
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