Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Recursive template?

Rephrased Question

I found that my original question wasn't clear enough and the repliers misunderstood my problem. So let me try to clarify:

Let's say I have two classes:

struct C { void(*m_func)(C*); };
struct D { std::function<void(D*)> m_func; };

Now I want to make a generic version of the two, so I do something like this:

template<typename Func>
struct G
{
Func m_func;
};

But now I don't know how to instantiate this class:

G<void(*)(G*)> c;  //error
G<std::function<void(G*)>> d;  //error

G<void(*)( G<void(*)(G<???>*)> *)> c;  //???
G<std::function<void( G<std::function<void(G<???>*)>> *)>> d;  //???

Original Question:

Hi,

I have a template class that can take a function pointer or a std::function object as its parameter. All is fine until that function uses a pointer of the template class in its signature:

#include <functional>

template<typename Func>
class C
{
public:
    C() {}
    Func m_func;
};

void foo()
{
    C<void(*)(C*)> c;
    C<std::function<int(C*)>> d;
}

Relevant compiler errors:

error C2955: 'C' : use of class template requires template argument list
error C3203: 'function' : unspecialized class template can't be used as a template argument for template parameter 'Func', expected a real type
error C2955: 'std::tr1::function' : use of class template requires template argument list

How do it solve this problem?

like image 316
twf Avatar asked Dec 13 '25 18:12

twf


1 Answers

You can't name the recursive template outside itself, but you can name it inside, as the parameter list is optional in a self-reference.

The problem then becomes one of telling the template how to pass itself to "something."

template< typename T >
struct fptr_taking_type {      // this template is essentially a function
    typedef void (*type)( T ); // from types to types, the result being
};                             // the typedef

template< typename T >
struct stdfn_taking_type {
    typedef function< void (*)( T ) > type;
};

template< template< typename > class F >
struct G {
    typename F< G * >::type m_func; // this declares the member variable
};

...

G< fptr_taking_type > q;
like image 157
Potatoswatter Avatar answered Dec 15 '25 09:12

Potatoswatter



Donate For Us

If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!