Recursive search using awk command

Question

I have 100 log files and I want awk to search for a given pattern between a given timestamp recursively. Log files look something like this

2010-03-24 07:00:01 ZZZZC941948879 RUFFLES 222.222.222.222 GET / - 80 - 220.181.7.113 HTTP/1.1       
2010-03-24 07:00:23 ZZZZC941948879 RUFFLES 222.222.222.222 GET 

Code is

 awk -v "b=$date1" -v "e=$date2" '$1 >= b && $1 <= e' log.txt > output
 grep -i "21things" output

I am able to search for the pattern but for single file only. Is it possible using awk command to search recursively?

Thanks for the help..!!

Answer 1

You can use find command to course through all files recursively in a directory and pass the file into awk. The following will show all the files where a match occurred. Change the <PATTERN> with required:

find . -type f -exec awk '/<PATTERN>/{print FILENAME; nextfile}' '{}' \;

The following will print out all lines matched along with filename:

find . -type f -exec awk '/<PATTERN>/{print FILENAME ":\t" $0;}' '{}' \;