I have the 4 bytes that represent an integer stored in 2 separate byte arrays. I would like to convert these into an Int32 WITHOUT copying to a third byte array and reading that using memorystream.
The reason the data is split across two byte arrays is because this is a simplified example of my issue which involves huge amounts of data that cannot fit into a single bytearray.
Is there any way to achieve this? I do not wish to concatenate the two byte arrays into a thrid because of the performance implications which are critical to me.
Moon
You can use a struct layout like this
[StructLayout(LayoutKind.Explicit, Size=4)]
struct UnionInt32Value
{
[FieldOffset(0)] public byte byte1;
[FieldOffset(1)] public byte byte2;
[FieldOffset(2)] public byte byte3;
[FieldOffset(3)] public byte byte4;
[FieldOffset(0)] public Int32 iVal;
}
Assign your bytes in the correct order then read your Int32 from iVal;
EDIT: Sample code
using System;
using System.Runtime.InteropServices;
namespace Test
{
class Program
{
[StructLayout(LayoutKind.Explicit, Size=4)]
struct UnionInt32Value
{
[FieldOffset(0)] public byte byte1;
[FieldOffset(1)] public byte byte2;
[FieldOffset(2)] public byte byte3;
[FieldOffset(3)] public byte byte4;
[FieldOffset(0)] public Int32 iVal;
}
public static void Main(string[] args)
{
UnionInt32Value v = new UnionInt32Value();
v.byte1=1;
v.byte2=0;
v.byte3=0;
v.byte4=0;
Console.WriteLine("this is one " + v.iVal);
v.byte1=0xff;
v.byte2=0xff;
v.byte3=0xff;
v.byte4=0xff;
Console.WriteLine("this is minus one " + v.iVal);
Console.Write("Press any key to continue . . . ");
Console.ReadKey(true);
}
}
}
Something like this?
int x = (array1[index] << 16) + array2[index];
Of course, you didn't specify a language, but that's the gist of it.
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