Read an input file one line at a time to pass as input to grep

Question

My requirement is to read a file and then run a grep command on the read line one at a time for all the lines in the file.

Filtering the required file which matches a pattern

find . -name *.ini -exec grep -w HTC {} \; -print | grep ini > input.files

cat input.files

./PLATFORM/android/build/integration/android/suites/android_Prefs_Devices_Comms_Suite/ini/android_0019.ini
./PLATFORM/android/build/integration/android/suites/android_Prefs_Devices_Comms_Suite/ini/android_0150.ini
./PLATFORM/android/build/integration/android/suites/android_Prefs_Devices_Comms_Suite/ini/android_0616_1.ini
./PLATFORM/android/build/integration/android/suites/android_SI_Query_Suite/ini/android_0547_4.ini
./PLATFORM/android/build/integration/android/suites/android_SI_Query_Suite/ini/android_0578.ini
./PLATFORM/android/build/integration/android/suites/android_PDL_Suite/ini/android_5203_1.ini
./PLATFORM/android/build/integration/android/suites/android_System_Maintenance_Suite/ini/android_0579_2.ini

Any idea how to read one line at a time from input.files and execute a grep command on that ?

cat input.files -exec grep -w HTC_One {} \;

Answer 1

There won't be any difference in the result if you say:

grep pattern file1
grep pattern file2

or

grep pattern file1 file2

Simply, use xargs:

cat input.files | xargs grep -w HTC_One