R get data.frame name in the function

Question

I wrote a function which does analysis with data.frame. In the function start, I print information what variables are taken in the function. So I want to print info of data.frame name which is used.

But I can not get data.frame name printed. It does not print the data.frame name, instead it prints its content, but not name. is it possible to print the name of data.frame which is passed to function internally in the function.

tmpFuction <- function(DF){

print("#############")
print("tmpFuction starts")
print(paste("DF",DF,sep="="))
print("#############")
return(1)
}
df1 <- data_frame(id=seq(1:4),x=rep(0,4))
df2 <- data_frame(id=c(1,2),x=c(0,4))
tmpFuction(10)
tmpFuction("a")
tmpFuction(df1)
tmpFuction(df2)

The output. For the last 2 examples I want to be printed:

[1] "#############"
[1] "tmpFuction starts"

[1] "DF=df1"

[1] "#############"

[1] "#############"
[1] "tmpFuction starts"

[1] "DF=df2"

[1] "#############"
[1] 1
> 

But I get:

> tmpFuction(10)
[1] "#############"
[1] "tmpFuction starts"
[1] "DF=10"
[1] "#############"
[1] 1
> tmpFuction("a")
[1] "#############"
[1] "tmpFuction starts"
[1] "DF=a"
[1] "#############"
[1] 1
> tmpFuction(df1)
[1] "#############"
[1] "tmpFuction starts"
[1] "DF=1:4"           "DF=c(0, 0, 0, 0)"
[1] "#############"
[1] 1
> tmpFuction(df2)
[1] "#############"
[1] "tmpFuction starts"
[1] "DF=c(1, 2)" "DF=c(0, 4)"
[1] "#############"
[1] 1
> 

Answer 1

deparse(substitute()) returns you the name of a variable, you can call it like this in your function:

DF <- data.frame(c(1,2)); print(paste("DF", deparse(substitute(DF)),sep="="))