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query date ranges postgresql

I have the following postgresql table;

ID  Date
 1  [2017-01-01,2051-01-01)
 2  [2017-01-01,2051-01-01)
 3  [2017-01-01,2051-01-01)
 4  [2017-01-01,2051-01-01)
 5  [2000-01-01,2017-01-01)
 6  [2000-01-01,2017-01-01)
 7  [2017-01-01,2051-01-01)
 8  [2017-01-01,2051-01-01)
 9  [2017-01-01,2051-01-01)
 10 [2017-01-01,2051-01-01)

How can I query in date ranges such that for June 2003 it returns ID 5 and 6.

like image 449
shahzad ise Avatar asked Jun 15 '26 06:06

shahzad ise


1 Answers

Use the containment operator <@:

with my_table(id, dates) as (
values
    (1, '[2017-01-01,2051-01-01)'::daterange),
    (2, '[2017-01-01,2051-01-01)'),
    (3, '[2017-01-01,2051-01-01)'),
    (4, '[2017-01-01,2051-01-01)'),
    (5, '[2000-01-01,2017-01-01)'),
    (6, '[2000-01-01,2017-01-01)'),
    (7, '[2017-01-01,2051-01-01)'),
    (8, '[2017-01-01,2051-01-01)'),
    (9, '[2017-01-01,2051-01-01)'),
    (10, '[2017-01-01,2051-01-01)')
)

select *
from my_table
where '2003-06-01'::date <@ dates;

 id |          dates          
----+-------------------------
  5 | [2000-01-01,2017-01-01)
  6 | [2000-01-01,2017-01-01)
(2 rows)    

Read about Range Functions and Operators.


You can also check whether a date range (not a single date) is contained by dates:

where daterange('2003-01-01', '2003-12-31') <@ dates;

or whether a date range overlaps dates:

where daterange('2003-01-01', '2003-12-31') && dates;
like image 94
klin Avatar answered Jun 17 '26 22:06

klin