I have 2 tables:
Student:
id name
2 ABC
13 DEF
22 GHI
Semester:
id student_id sem marks
1 2 1 {"math":3, "physic":4, "chemis":5}
2 2 2 {"math":2.5, "physic":4.5, "chemis":5}
3 2 3 {"math":3, "physic":3.5, "chemis":4}
5 13 1 {"math":3, "physic":4, "chemis":5}
6 13 2 {"math":3, "physic":4, "chemis":5}
So e.g with student_id=2:
average marks = ((3+4+5)/3)+(2.5+4.5+5)/3+(3+3.5+4)/3)/3 = 3.83
Is there any way to query average marks group by student ID?
student_id average number_of_sems
2 3.83 3
13 xxx 2
I'm trying to count by subject:
SELECT
t1.student_id,
t1.count,
(SELECT sum(xx.count)
FROM
(SELECT (marks:: JSON ->> 'math') :: DOUBLE PRECISION AS count
FROM "Semester"
WHERE student_id= t1.student_id) AS xx)
FROM
(
SELECT
student_id,
count(1)
FROM "Semester"
GROUP BY student_id
) AS t1;
But still don't know how to continue. This might be bad solution.
This includes the students without marks:
SELECT st.id, avg(m.value)
FROM student st
LEFT JOIN semester se
ON st.id = se.student_id
LEFT JOIN LATERAL (SELECT value::numeric
FROM jsonb_each_text(se.marks)
) m
ON TRUE
GROUP BY st.id;
┌────┬────────────────────┐
│ id │ avg │
├────┼────────────────────┤
│ 2 │ 3.8333333333333333 │
│ 13 │ 4.0000000000000000 │
│ 22 │ │
└────┴────────────────────┘
(3 rows)
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