Python construct datetime having weekday with other time parameters

Question

I need to construct datetime object from different parameters. For example, I get these parameters:

• integer number from 0 to 6. This one indicates weekday.
• hour and minutes in float format (from 0.0 to 24.0).

And then I know which week of the current year it is going to be. So, for example, let say that datetime should be from 2014-07-18 00:00:00 to 2014-07-24 23:59:00 (seconds can be ignored and left at 00). So to get exact datetime I need to use above defined parameters.

Let say I would get these parameters 4 (meaning Friday), and 9.5 (meaning 09:30).

So by doing such construction, I should get a date that would be: 2014-07-22 09:30:00. How could accomplish such thing?

Do I need to somehow get for example day of the month by knowing which is the week of the year and which weekday it is?

P.S. A bit more detailed example of what I'm trying to accomplish

from datetime import datetime

today = datetime.today() #using this to get the week I'll be working with.

today = today.replace(day=?) #how to get which day I 
#need to enter by having weekday and knowing that week is the present one?

Answer 1

You could do something like that, if your parameters are weekday and t (time):

from datetime import timedelta
monday = today - timedelta(days=today.weekday())
result = (monday + timedelta(days=weekday)).replace(hour=int(t), minutes=int((t - int(t)) * 60))