Python cant handle exceptions from zipfile.BadZipFile

Question

Need to handle if a zip file is corrupt, so it just pass this file and can go on to the next.

In the code example underneath Im trying to catch the exception, so I can pass it. But my script is failing when the zipfile is corrupt*, and give me the "normal" traceback errors* istead of printing "my error", but is running ok if the zipfile is ok.

This i a minimalistic example of the code I'm dealing with.

path = "path to zipfile" 

from zipfile import ZipFile

with ZipFile(path) as zf:
    try:
        print "zipfile is OK"
    except BadZipfile:
        print "Does not work "
        pass

part of the traceback is telling me: raise BadZipfile, "File is not a zip file"

Answer 1

You need to put your context manager inside the try-except block:

try:
    with ZipFile(path) as zf:
        print "zipfile is OK"
except BadZipfile:
    print "Does not work "

The error is raised by ZipFile so placing it outside means no handler can be found for the raised exception. In addition make sure you appropriately import BadZipFile from zipfile.