Python any() method results

Question

Im wondering how the following result will yield True?

>>> x=['0']
>>> valid_diff=['0','1','2','3']
>>> result =any(x for each in x if x in valid_diff)
>>> result 
False

I would the expect the result to be True as the first element itself will be True.

Any thoughts, Im sure im missing something here..

Answer 1

You have made a typo with your variable names, you should be checking if each in valid_diff not if x in valid_diff and each for each not x for each

Answer 2

Apart from the typo I think there's no need of storing each here, just use:

#returns True if any item in x is found in valid_diff
>>> any(each in valid_diff for each in x)
True

or strictly sticking to what you were trying to do then use this:

any(each in valid_diff and each for each in x)
#will return `True` only if any item found in valid_diff is a Truth value as well.

Truth Value Testing