Python: 1 to 100 using While statement in 10 rows

Question

I am trying to print 1 to 100 using while statement. Well, that is easy

 n =100
 i=0
 while i<n:
      i=i+1
      print (i)

But the problem is how to put 1 to 10 in a row, 11 to 20 in a row, and finally to 91 to 100 in a row. Could you tell me the way?

Answer 1

You can use zip and iter:

lst = [i for i in zip(*[iter(range(1,101))]*10)]

Change the last number to the size of the chunks you want; in this case it is 10.

Output:

>>> lst
[(1, 2, 3, 4, 5, 6, 7, 8, 9, 10), (11, 12, 13, 14, 15, 16, 17, 18, 19, 20), (21, 22, 23, 24, 25, 26, 27, 28, 29, 30), (31, 32, 33, 34, 35, 36, 37, 38, 39, 40), (41, 42, 43, 44, 45, 46, 47, 48, 49, 50), (51, 52, 53, 54, 55, 56, 57, 58, 59, 60), (61, 62, 63, 64, 65, 66, 67, 68, 69, 70), (71, 72, 73, 74, 75, 76, 77, 78, 79, 80), (81, 82, 83, 84, 85, 86, 87, 88, 89, 90), (91, 92, 93, 94, 95, 96, 97, 98, 99, 100)]

Then print each number inside the list:

for i in lst:
    for j in i:
        print(j, end=" ")
    print()

Output:

1 2 3 4 5 6 7 8 9 10 
11 12 13 14 15 16 17 18 19 20 
21 22 23 24 25 26 27 28 29 30 
31 32 33 34 35 36 37 38 39 40 
41 42 43 44 45 46 47 48 49 50 
51 52 53 54 55 56 57 58 59 60 
61 62 63 64 65 66 67 68 69 70 
71 72 73 74 75 76 77 78 79 80 
81 82 83 84 85 86 87 88 89 90 
91 92 93 94 95 96 97 98 99 100 

So overall you have:

lst = [i for i in zip(*[iter(range(1,101))]*10)]

for i in lst:
    for j in i:
        print(j, end=" ")
    print()

EDIT:

As someone mentioned this only works in python 3. It can be done in python 2 by simply changing end=" " to ,:

lst = [i for i in zip(*[iter(range(1,101))]*10)]

for i in lst:
    for j in i:
        print j,
    print

EDIT 2:

To do this with a while loop:

counter = 1
n = 100

while counter < n+1:

    if counter % 10 == 0:
        print(counter)
    else:
        print(counter, end=" ") #Change this line to print counter, for python version 2
    counter += 1