Put string between two % in Golang

Question

I have a string in Golang called mystring and I want to put it between 2 percentage signs (like this %mystring%). However until now I wasn't able to do it.

The things that I have tried are:

value := fmt.Sprintf("%%s%",mystring)
value := fmt.Sprintf("%s%s%s","%",mystring,"%")
value := fmt.Sprintf("/% %s/%",mystring)

But when I print it, in the end I receive a nil. Example: the value of mystring is "HelloWorld" then I get: %HelloWorld%nil

Right now I am receiving this as result:

/%s/%!(NOVERB)%!(EXTRA string=HelloWorld)<nil>

So, what am I missing?
Thanks.

Answer 1

You need to escape the %'s in format string using another %:

value := fmt.Sprintf("%%%s%%",mystring)

Answer 2

Use %% in your format string for an actual %.

For example:

func main() {
    mystring := "hello"
    value := fmt.Sprintf("%%%s%%", mystring)
    fmt.Println(value)
}

Prints: %hello%

This is clearly documented at the beginning of the docs for fmt:

%% a literal percent sign; consumes no value