process substitution not working in bash script

Question

I am stuck with weird issue. Process substitution is not working when it's been called from bash script, however it work when I shoot it from terminal.

Here is example: While running over terminal.

terminal>echo "$x"
a b c
d e f
g h i
j k l

terminal>echo "$y"
1
2
3
4

terminal>paste <(echo "$x") <(echo "$y") -d' '
a b c 1
d e f 2
g h i 3
j k l 4

Here is example: Sample script

---

    #!/bin/bash
    x='a b c
    d e f
    g h i
    j k l'


    y='1
    2
    3
    4'

    paste <(echo "$x") <(echo "$y") -d' '

---

When I above script , I get following error:

test: line 12: syntax error near unexpected token `('
test: line 12: `paste <(echo "$x") <(echo "$y") -d' ''

Following are the details of shell I am using.

echo $SHELL
/bin/bash
bash --version
GNU bash, version 4.2.47(1)-release (x86_64-suse-linux-gnu)

Is there any alternate way to bypass this issue ? Not necessarily I want to stick to process substitution.

Desired o/p:

a b c 1
d e f 2
g h i 3
j k l 4

Answer 1

Process substitution does not work when bash is in POSIX mode. Please disable POSIX and try again.

To disable: This will cause process substitution to work .

set +o posix

To enable: : This will cause process substitution not to work.

set -o posix