i'm trying to POST a file to a webservice using CURL (that's what I need to use so I can't take twisted or something else). The problem is that when using pyCurl the webservice doesn't receive the file i'm sending, as in the case commented at the bottom of the file. What am I doing wrong in my pyCurl script? Any ideeas?
Thank you very much.
import pycurl
import os
headers = [ "Content-Type: text/xml; charset: UTF-8; " ]
url = "http://myurl/webservice.wsdl"
class FileReader:
def __init__(self, fp):
self.fp = fp
def read_callback(self, size):
text = self.fp.read(size)
text = text.replace('\n', '')
text = text.replace('\r', '')
text = text.replace('\t', '')
text = text.strip()
return text
c = pycurl.Curl()
filename = 'my.xml'
fh = FileReader(open(filename, 'r'))
filesize = os.path.getsize(filename)
c.setopt(c.URL, url)
c.setopt(c.POST, 1)
c.setopt(c.HTTPHEADER, headers)
c.setopt(c.READFUNCTION , fh.read_callback)
c.setopt(c.VERBOSE, 1)
c.setopt(c.HTTP_VERSION, c.CURL_HTTP_VERSION_1_0)
c.perform()
c.close()
# This is the curl command I'm using and it works
# curl -d @my.xml -0 "http://myurl/webservice.wsdl" -H "Content-Type: text/xml; charset=UTF-8"
PyCurl seems to be an orphaned project. It hasn't been updated in two years. I just call command line curl as a subprocess.
import subprocess
def curl(*args):
curl_path = '/usr/bin/curl'
curl_list = [curl_path]
for arg in args:
# loop just in case we want to filter args in future.
curl_list.append(arg)
curl_result = subprocess.Popen(
curl_list,
stderr=subprocess.PIPE,
stdout=subprocess.PIPE).communicate()[0]
return curl_result
curl('-d', '@my.xml', '-0', "http://myurl/webservice.wsdl", '-H', "Content-Type: text/xml; charset=UTF-8")
Try to do the file upload in this manner:
c.setopt(c.HTTPPOST, [("filename.xml", (c.FORM_FILE, "/path/to/file/filename.xml"))])
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