Print everything on line after match [duplicate]

Question

I have an large textfile that contains an unique string in the middle. What i want to do is to print everything AFTER the string by using grep.

cat textfile | grep "target_string" This highlights target_string but prints the whole file  cat textfile | grep -o "target_string" This prints only target_string  cat textfile | grep -o "target_string*" This prints only target_string 

How can i print everything after target_string and nothing before?

Answer 1

Strangely, the accepted answer printed out the whole line, where I just wanted all the info after the target string. This worked for me:

sed -n 's/target_string//p' filename 

Adapted from this post

Answer 2

With GNU grep, try -B0 -A999999999 or similar. A better choice might be awk:

awk '/target_string/ {seen = 1}      seen            {print}' 

If (your problem specification is slightly unclear) you don't also need to print the matching line, sed is even shorter:

sed '1,/target_string/d'