PostgreSQL regular expression

Question

I have a string like 'ABC3245-bG1353BcvG34'. I need to remove the hyphen including all the letters after hyphen.

so the above string should be ABC3245135334

I tried the below code:

select substring('ABC3245-bG1353BcvG34' from 1 for (position('-' in 'ABC3245-bG1353BcvG34')-1))||regexp_replace(substring('ABC3245-bG1353BcvG34' from (position('-' in 'ABC3245-bG1353BcvG34') +1) for length('ABC3245-bG1353BcvG34')),'[a-zA-Z]','')

but not able to remove letters after the hyphen.

Answer 1

I need to remove the hyphen including all the letters after hyphen.

so the above string (ABC3245-bG1353BcvG34) should be ABC3245135334

This suggests that all numbers should remain after the hyphen (in their original order). If that's what you want, you cannot do this with a single regex. Assuming you can have only 1 hyphen in your input:

SELECT substring(input.value from '^[^-]*') ||
       regexp_replace(substring(input.value from '[^-]*$'), '\D+', '', 'g')
FROM (SELECT 'ABC3245-bG1353BcvG34'::text AS value) AS input

If you can have multiple hyphens in your input, please define how to handle characters between hyphens.

Answer 2

Fixed version

SELECT a[1] || regexp_replace(a[2], '\D', '', 'g')
FROM   string_to_array('ABC3245-bG1353BcvG34', '-') AS a

Or, more convenient to deal with a set (like a table):

SELECT split_part(str, '-', 1)
    || regexp_replace(split_part(str, '-', 2), '\D', '', 'g')
FROM  (SELECT 'ABC3245-bG1353BcvG34'::text AS str) tbl

Removes all non-digits after the hyphen. (Assuming there is only one hyphen.) Result:

ABC3245135334

First version

Missed that OP wants to remove all letters after -.

SELECT regexp_replace('ABC3245-bG1353BcvG34', '-\D*', '')

Result:

ABC32451353BcvG34

Regex explained:

- .. literal hyphen -
\D .. class shorthand for "non-digits".
* .. 0 or more times

Removes the first hyphen and everything that follows until the first digit.