Please explain Javascript image rotation code

Question

I'm using the following code to create a basic image rotation feature, & I want to get a better understanding of how it's working. I get most of it, but the line in the rotate function where it uses the 'strict' equals & the ternary operator, i.e. (i === (imgs.length -1) ) ? i=0 : i++ ;) is a bit confusing. I know it's incrementing the counter, but what's it doing before that?

var i, imgs, pic;

function rotate()
{
    pic.src = imgs[i] ;
    (i === (imgs.length -1) ) ? i=0 : i++ ;
    setTimeout( rotate, 2500 );
}

function init()
{
    pic = document.getElementById("pic");

    imgs = [ 'images/shimano_offer.jpg', 'images/kids_bikes1.jpg', 'images/cycle_to_work.jpg' ] ;

    var preload= new Array();
    for( i=0; i< imgs.length; i++ )
    {
        preload[ i ] = new Image();
        preload[ i ].src = imgs[ i ];
    }

    i=0;

    rotate();
}

Code is from http://ineasysteps.com/products-page/all_books/javascript-in-easy-steps-4th-edition/

Answer 1

The line

(i === (imgs.length -1) ) ? i=0 : i++ ;

Could (and should) be written as:

if (i === (imgs.length - 1)) {
    i = 0;
} else {
    i += 1;
}

Yes, the former is less bytes, but much more difficult to understand and debug.

Edit: Norguard points out a valid way of using the ternary form for this. I use ternaries, but in this case I would not because I would likely want to put a breakpoint on the "i = 0" condition at some point when debugging. If you don't anticipate needing a breakpoint, his method is more compact and concise, and possibly preferable.