php preg_replace() indexed array issue

Question

This is the program:

$string = 'Inquiry {{inquiry:number}} is assigned to {{details_1}}';
$patterns = array();
$patterns[0] = '/({{)(.*)(}})/U';
$patterns[1] = '/({{)(.*)(}})/U';
$replacements = array();
$replacements[1] = 15;
$replacements[0] = 20;
ksort($patterns);
ksort($replacements);
echo preg_replace($patterns, $replacements, $string);

It should give the output:

Inquiry 20 is assigned to 15

But what I am getting:

Inquiry 20 is assigned to 20

I was wondering is it a problem with preg_replace?

Note: I am trying to replace the string inside {{ .. }} including the curly brackets, with the corresponding values.

Answer 1

By default, preg_replace replace all occurrences. Simply add optional parameter “limit” to your script and it will work:

echo preg_replace( $patterns, $replacements, $string, 1 );

Answer 2

$replArray = array(
  '{{inquiry:number}}',
  '{{details_1}}'
);

$valueArray = array (15,20);
echo str_replace($replArray,$valueArray,$patern);

If you want use the template you need parsing the variable, and checked right queue, for example {} - this right , {{} - don't right.