PHP JSON_DECODE ARRAY

Question

I am using following code to decode json array

$json_contacts ='[{"addr_name":"1","addr_phone":"010-1111-1111"},{"addr_name":"2","addr_phone":"010-1111-1112"},{"addr_name":"3","addr_phone":"010-1111-1113"},{"addr_name":"4","addr_phone":"010-1111-1114"}]';

$contact = json_decode($json_contacts, true);
echo $json_contacts;
echo "\n";
echo $contact;
echo "\nTHE END";

I am getting following result

[{"addr_name":"1","addr_phone":"010-1111-1111"},{"addr_name":"2","addr_phone":"010-1111-1112"},{"addr_name":"3","addr_phone":"010-1111-1113"},{"addr_name":"4","addr_phone":"010-1111-1114"}]

THE END

Why is my JSON_DECODE not decoding the array properly?

Answer 1

Try this:

<?php
$json_contacts ='[{"addr_name":"1","addr_phone":"010-1111-1111"},{"addr_name":"2","addr_phone":"010-1111-1112"},{"addr_name":"3","addr_phone":"010-1111-1113"},{"addr_name":"4","addr_phone":"010-1111-1114"}]';

$contact = json_decode($json_contacts, true);
echo $json_contacts;
echo "\n";
echo '<pre>';
print_r( $contact);

echo '</pre>';
echo "\nTHE END";

---

Because you echo your previous $json_contacts and you didn't turn on PHP notice. You cannot echo $contact because it's an array.