PHP If array_key_exists, variable equals array value: How?

Question

I combined two arrays to create the following array, named $group_wages_array:

Array ( [1] => 500 [4] => 44 [6] => 80 [3] => 11.25 )

I am trying to test if the array key matches X, set a variable as it's value. Here's what I have:

NOTE: This whole thing is executed in a while loop, so the value of $thegroup['group_id'] will change. I've set it's value as "6" for this example.

$thegroup['group_id'] = "6" // This particular group (for simplicity)

if (array_key_exists($thegroup['group_id'], $group_wages_array)) {

    $this_wages = // Need this to be 80... how do I do it?

}

So, how do I get $this_wages to equal the key value?

Answer 1

You just use the key from the array to get it:

$thegroup['group_id'] = "6" // This particular group (for simplicity)

if (array_key_exists($thegroup['group_id'], $group_wages_array)) {
    $this_wages = $group_wages_array[$thegroup['group_id']];
}

Also, the array keys are not 0,1,2,etc because you explicitly set them in Array ( [1] => 500 [4] => 44 [6] => 80 [3] => 11.25 )

Answer 2

You are trying to do:

$group_wages_array[6];

And

$thegroup['group_id'] = 6;

You can substitute this in as the key.

if (array_key_exists($thegroup['group_id'], $group_wages_array)) {
    $this_wages = $group_wages_array[$thegroup['group_id']];   
}