Menu
i am sorry for the dummy question. Here is my simple PHP form with two SQL tables and with the ADD submit button I would like to move people from Test1 to Test2. Many thing are fine:( only the submit button does't work therefore no feedback from Test2 table.
Revised: Submit now works great
Q2 - still don't get the checkboxs to work:( - please
Could somebody show me how to track back such an error like this please?
<?php include("db_connect.php");?>
<html>
<head></head>
<body>
<form method="post" action="moving.php">
<table border="1">
<tr>
<td>
<?php
$left='SELECT * FROM test1 ORDER BY name ASC';
$result1=mysql_query($left);
$count=mysql_num_rows($result1);
while($resulta = mysql_fetch_array($result1)) {
?>
<input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $resulta['id']; ?>"/> <? echo $resulta['name']; ?>
<br />
<?php } ?>
</td>
<td><input type="submit" id="add" name="add" value="Add" /></td>
<td>
<?php
$rigth='SELECT * FROM test2,test1 WHERE test2.collect=test1.id ORDER BY test1.name ASC';
$result2=mysql_query($right);
while($resultb = mysql_fetch_array($result2)) {
echo $resultb['id'] ;
echo "<br />";
}
?>
</td>
</tr>
</table>
<?php
// Check if add button active, start this
if (isset($_POST['add'])) {
for ($i=0;$i<$count;$i++) {
$add_id = $checkbox[$i];
if ($add_id=='1') {
$sql = "INSERT INTO test2 (status, collect) VALUES(1, 1)";
$result = mysql_query($sql);
}
}
// if successful redirect to delete_multiple.php
if ($result){
echo "<meta http-equiv=\"refresh\" content=\"0;URL=moving.php\">";
}
}
mysql_close();
?>
</form>
</body>
</html>
thanks:) from a beginner
618
where does $count come from?
Try using count($_POST['checkbox']) instead on your INSERT statement. Then you can iterate over the checkboxes using:
for ($c = 0; $c < count($_POST['checkbox']); $c++){
$checkbox = $_POST['checkbox'][$c];
...INSERT action...
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
