PHP array unset

Question

Here code (executed in php 5.3.5 and 5.2.13):

$res = array(1, 2, 3);

unset($res[0]);

for($i = 0; $i < sizeof($res); $i++)
{
  echo $res[$i] . '<br />';
}

In results i see

<br />2<br />

Why only one element, and first empty? Can`t understand. When doing:

print_r($res);

See:

Array ( [1] => 2 [2] => 3 )

Thanx for help!

Answer 1

This is because you start with $i = 0; rather than 1 which is the new first index. The last element is missing because it stops before the second (previously third) element since the size has been reduced to 2. This should get the results you wish:

foreach($res as $value) {
    echo $value . '<br />';
}

Answer 2

PHP doesn't rearrange the keys on unset. Your keys after the unset are 1 and 2. In the for cycle, i gets the 0 and 1 values. Using this snippet you should init i to 1, the first key of the array.

Hint 1: Use foreach to itearate over an array.
Hint 2: Don't use aliases. Use count instad of sizeof.