Passing block into a method - Ruby [duplicate]

Question

I have a little question on passing block.

def a_method(a, b)
  a + yield(a, b)
end

This works fine.

k = a_method(1, 2) do |x, y| 
  (x + y) * 3 
end
puts k

But this won't work.

puts a_method(1, 2) do |x, y| 
  (x + y) * 3 
end
# LocalJumpError: no block given (yield)

Can anyone kindly explain this to me?

Thanks. Example taken from Metaprogramming Ruby by Paolo Perrotta. Great book.

Answer 1

The difference between do .. end and curly braces is that the curly braces bind to the rightmost expression, while do .. end bind to the leftmost one. Observe the following examples:

def first(x=nil)
  puts "  first(#{x.inspect}): #{block_given? ? "GOT BLOCK" : "no block"}"
  "f"
end

def second(x=nil)
  puts "    second(#{x.inspect}): #{block_given? ? "GOT BLOCK" : "no block"}"
  "s"
end

first second do |x| :ok end #   second(nil): no block
                            # first("s"): GOT BLOCK

first second {|x| :ok }     #   second(nil): GOT BLOCK
                            # first("s"): no block

In the first case, the block made with do..end will be bound to the first function (leftmost). In the second case the block made with curly brackets will be bound to the second function (rightmost).

Usually it's good idea to use parentheses if you have two functions and a block - just for readability and to avoid mistakes.

It's very easy to accidentally pass a block to puts method, just as in your question.