pass command line arguments to python interpreter without a script file

Question

I want do start the python interpreter and debug with sys.argv. I do not want to provide a python file. If I provide a file, the interpreter executes the file and finishes.

Is there a way to archive this?

python argA argB
...
>>> import sys
>>> print sys.argv
['argA','argB']

Answer 1

This is pretty much what you want:

$ python - argA argB

The first argument will show up as -, though - think of it as a pseudo script name. I don't think you can get away from that.