Pass Arc into async handler [duplicate]

Question

I have something like this:

use std::sync::Arc;

fn main() {
    let arc = Arc::new(42);
    move || { arc.clone() };
    move || { arc.clone() };
}

I am getting:

error[E0382]: capture of moved value: `arc`
 --> src/main.rs:6:19
  |
5 |         move || { arc.clone() };
  |         ------- value moved (into closure) here
6 |         move || { arc.clone() };
  |                   ^^^ value captured here after move
  |
  = note: move occurs because `arc` has type `std::sync::Arc<i32>`, which does not implement the `Copy` trait

I understand why I am getting this: the clone isn't called before arc is passed to the closure. I can fix this by defining each closure in a function and clone the Arc before passing it to the closure, but is there another option?

Answer 1

There is no way around it. You should clone the Arc before it is used in a closure. The common pattern is to re-bind the cloned Arc to the same name in a nested scope:

use std::sync::Arc;

fn main() {    
    let arc = Arc::new(42);
    {
        let arc = arc.clone();
        move || { /* do something with arc */ };
    }
    {
        let arc = arc.clone();
        move || { /* do something else with arc */ };
    }
}

This is usually done together with thread::spawn():

use std::sync::{Arc, Mutex};
use std::thread;

const NUM_THREADS: usize = 4;

fn main() {
    let arc = Arc::new(Mutex::new(42));
    for _ in 0..NUM_THREADS {
        let arc = arc.clone();
        thread::spawn(move || {
            let mut shared_data = arc.lock().unwrap();
            *shared_data += 1;
        });
    }
}