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Pass an array containing input arguments to a function in Julia

Tags:

arrays

julia

How can I pass an array containing the dimensions I desire to a function like ones or rand in Julia?

For example, I'd like to execute

dims = [3 4]
rand(dims)

and then receive something like

3×4 Array{Float64,2}:
 0.300811  0.140124  0.756915   0.268328 
 0.732461  0.900773  0.251334   0.0338452
 0.54227   0.439385  0.0812104  0.612996 

as the output.

Executing the first code block returns a single number selected at random from the array dimen = [3 4], however, and rand(dims = dimen) returns a ERROR: function rand does not accept keyword arguments error.

Is there a way to do what I'm hoping to?

like image 974
userManyNumbers Avatar asked May 20 '26 03:05

userManyNumbers


2 Answers

What you are looking for is the "splat" operator ..., as described in the documentation:

On the flip side, it is often handy to "splat" the values contained in an iterable collection into a function call as individual arguments. To do this, one also uses ... but in the function call instead

In your case:

julia> dims = [3 4];
julia> rand(dims...)

3×4 Array{Float64,2}:
 0.664496  0.190208  0.167208  0.172296
 0.632465  0.374373  0.417636  0.354948
 0.743741  0.740435  0.602339  0.401814
like image 77
PaSTE Avatar answered May 23 '26 20:05

PaSTE


Use the splat operator:

julia> xs = [3 4]
1×2 Array{Int64,2}:
 3  4

julia> rand(xs...)
3×4 Array{Float64,2}:
 0.569082   0.953     0.44541   0.12763 
 0.0529293  0.470243  0.770411  0.992597
 0.15326    0.248442  0.805518  0.246996

The splat operator will interpolate the array into the function call's argument list.

like image 34
David Varela Avatar answered May 23 '26 22:05

David Varela



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