parsing each line in text file java

Question

I have a text file that has the following lines:

150004|2012|12|15|0|0|3|0|0|-3.2411|83.9962|156.3321|1.1785|205.3125|2.0599
150004|2012|12|15|0|10|3|0|0|-3.4206|85.9575|150.4877|1.4142|226.7578|2.4276
150004|2012|12|15|0|20|3|0|0|-2.2696|86.2675|149.3848|2.1553|225.7031|3.4387

every '|' sign indicates it has a column. I have to extract the info from each line that is inside of '|' signs. When I try the following code:

File filer = new File("C:\\Users\\Ali Y. Akgul\\Desktop\\150004_15122012_G.txt");
        try (BufferedReader reader = new BufferedReader(new FileReader(filer))) {
            while (true) {
                String line = reader.readLine();
                if (line == null) {
                    break;
                }
                String[] fields = line.split("|");
                // process fields here
                for(int i=0;i<=fields.length;i++){
                    System.out.println(fields[i]);
                }
            }
        }
}

it gives me:

1
5
0
0
0
4
|
2
0
1
2
|
1
2
|
1
5
|
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 76
0
|
0
|
3
|
0
|
0
|
-
3
.
2
4
    at testenv.TestEnv.main(TestEnv.java:31)
1
1
|
8
3
.
9
9
6
2
|
1
5
6
.
3
3
2
1
|
1
.
1
7
8
5
|
2
0
5
.
3
1
2
5
|
2
.
0
5
9
9
Java Result: 1

How can I parse it correctly?

Answer 1

It is because that String.split uses a regex.

In regexes, the | character is a special character meaning either the pattern on the left OR on the right of the character. It has to be escaped with a backslash (\\)

The correct syntax is:

String[] fields = line.split("\\|");

Also, take nto that I didn't see the issue with the for loop, but that needs fixing too, that is why the ArrayOutOfBoundsException pops up its ugly head...

Answer 2

for(int i=0;i<=fields.length;i++) 

needs to be

for(int i=0;i<fields.length;i++)

(The '<=' must be '<')

Also the issue with your regexp pointed out in other answers.