Output of a pointer program [closed]

Question

I know little about pointers.

I came across the following program. The output seems normal but what is actually going going on I could not figure it out.

#include<stdio.h>
#include<conio.h>
void main()
{
     int k;
     int a[] = {1,2,3}; int *b[3] ; int **c[3];
     int ***d[3]; int ****e[3]; int*****f[3];
     for (k = 0 ; k <3; k++)
     {
         b[k] = a + k; c[k] = b + k ; d[k] = c + k;
         e[k] = d + k ; f[k] = e + k;

     }
     for (k = 0 ; k <3; k++)
     {
        printf("%3d", *b[k]); printf("%3d", **c[k]);
        printf("%3d", ***d[k]); printf("%3d", ****e[k]);
        printf("%3d\n", *****f[k]);
     }
}

Answer 1

The first for loop is just basic pointer arithmetic. a[] holds ints, each array after that holds a pointer.
b[] is a pointer to int
c[] is a pointer to pointer to int
etc

So it's something like this in memory:

Memory Address:      0x00441234 <---+   0x00441238 <----+     0x0044123C <---+
                     **********     |   **********      |     **********     |
var name:            * a (+0) *     |   * a (+1) *      |     * a (+2) *     |
                     **********     |   **********      |     **********     |
value:               *   1    *     |   *   2    *      |     *   3    *     |
                     **********     |   **********      |     **********     |
                                    |                   |                    |
                                    |                   |                    |
                  +-> 0x00442345    | +->0x00442349     | +->0x0044234D      |
                  |   ************  | |  ************   | |  ************    |
                  |   *  b (+0)  *  | |  *  b (+1)  *   | |  * b  (+2)  *    |
                  |   ************  | |  ************   | |  ************    |
                  |   *0x00441234* -+ |  *0x00441238* --+ |  *0x0044123C*  --+
                  |   ************    |  ************     |  ************     
                  |                   |                   |
                  |                   |                   |
                  |   0x00443345      | 0x00443349        | 0x0044334D      
                  |   ************    | ************      | ************    
                  |   *  c (+0)  *    | *  c (+1)  *      | * c  (+2)  *    
                  |   ************    | ************      | ************    
                  +-- *0x00442345*    +-*0x00442349*      +-*0x0044234D* 
                      ************      ************        ************     

And each element of D points to each element of C, and so on. The end result being you're setting each element in each of the arrays (via some chain of pointers) back to the elements of a. And then in the second for loop you're printing the elements of a[] over and over again.