Opening program by double-clicking associated file, can't get filename!

Question

I have a program that has a file type associated with it (*.cqd). When the user double clicks a .cqd file, it opens up my program just fine, but I can't for the life of me get the name/path of the file used to open the program.

I've tried the following code:

public static void Main(string[] args)
{
    foreach (string s in args)
    {
        MessageBox.Show("MAIN: " + s);
    }
}

Which only gives me the path of the program itself.

I've also tried:

foreach (string arg in Environment.GetCommandLineArgs())
{
     MessageBox.Show(arg);
}

Which has the same effect. I'm having a hard time finding information on the topic because my searches give me "How do I open a file with it's associated program?" rather than the problem I'm having. Any help I can get would be appreciated.

NINJA EDIT: This is not a WPF project. Sorry I wasn't specific on that. I also fixed a quick typo.

FOUND THE PROBLEM! When I publish the application, it publishes to a .application file. I went into the project's /bin/release/ folder and found the .exe file. When I drag a file onto the .exe, it properly passes the path into the arguments. Guess I need to read up more on why this is, and if I can get the .application file to work with arguments, seeing as how it has the auto-update of ClickOnce in it.

Thank you all for your help! If there's anything I need to do to close this thread, please let me know.

Answer 1

AppDomain.CurrentDomain.SetupInformation.ActivationArguments.ActivationData[0]

Works as well for ClickOnce activations