'NoneType' object is not subscriptable in python

Question

#i'm just testing it 

lst=[3, 2, 4, 5,1]

print([i for i in lst if i % 2 != 0].sort()[0])

#i haven't tried any thing        

#I expect the output 1

Answer 1

sort() sorts a list in place and returns None. Looks like you meant to use sorted instead:

print(sorted([i for i in lst if i % 2 != 0])[0])

Note, however, there's no need to sort the list if you just take its first element. You could use min instead for the same result with a better performance (O(n) instead of O(nlog(n)):

print(min([i for i in lst if i % 2 != 0]))

Answer 2

sort() is modifying method and returns None

This one works:

lst=[3, 2, 4, 5,1]
odds = [i for i in lst if i % 2 != 0]
ods.sort()
print(ods[0])