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The default and the lowest value of a DateTime object is January 1, 0001 00:00:00 (midnight).
The custom format string is "ddd, dd MMM yyyy HH':'mm':'ss 'GMT'".
The value of this constant is equivalent to 00:00:00.0000000 UTC, January 1, 0001, in the Gregorian calendar. MinValue defines the date and time that is assigned to an uninitialized DateTime variable. The following example illustrates this. C# Copy.
Gets a DateTime object that is set to the current date and time on this computer, expressed as the local time. public: static property DateTime Now { DateTime get(); }; C# Copy.
No, they are identical.
default(), for any value type (DateTime is a value type) will always call the parameterless constructor.
If you want to use default value for a DateTime parameter in a method, you can only use default(DateTime).
The following line will not compile:
private void MyMethod(DateTime syncedTime = DateTime.MinValue)
This line will compile:
private void MyMethod(DateTime syncedTime = default(DateTime))
The answer is no. Keep in mind that in both cases, mdDate.Kind = DateTimeKind.Unspecified.
Therefore it may be better to do the following:
DateTime myDate = new DateTime(1, 1, 1, 0, 0, 0, DateTimeKind.Utc);
The myDate.Kind property is readonly, so it cannot be changed after the constructor is called.
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