Consider following code:
#include <variant>
class A {};
class B {};
template<typename... Ts, typename Variant>
bool constexpr is_of(const Variant& variant)
{
return std::visit(
[](const auto& v) {
using V = std::decay_t<decltype(v)>;
return (std::is_same_v<V, Ts> || ...);
},
variant);
}
int main()
{
using Variant = std::variant<A, B>;
static_assert(is_of<A>(Variant{A{}}));
static_assert(!is_of<B>(Variant{A{}}));
static_assert(is_of<B>(Variant{B{}})); // Fails
static_assert(!is_of<A>(Variant{B{}})); // Fails
static_assert(!is_of<int>(Variant{A{}}));
static_assert(!is_of<int>(Variant{B{}}));
return 0;
}
is_of is a function which returns whether the value in a variant matches a range of types.
Why do the two static_asserts fail?
GCC and clang behave as expected.
I was not able to reduce the example even more.
The visit and the fold expression seem to be crucial, when I expand it using if constexpr, it works as expected.
https://godbolt.org/z/Wbd3GPzbc
Yes, it was a bug in MSVC, which is fixed in Visual Studio 2022 version 17.12, where all static_asserts in your program are accepted.
See https://developercommunity.visualstudio.com/t/Wrong-evaluation-of-fold-expression-insi/10730639
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